Math, asked by prasannarajan67, 1 year ago

rationalise the denominator
3*root3+1

Answers

Answered by drbhk2021
2

Answer:

 \frac{1}{3 \sqrt{3} + 1 }  =  \frac{1}{3 \sqrt{3}  + 1}  \times  \frac{3 \sqrt{3 } - 1 }{3 \sqrt{3 } - 1 } \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  =  \frac{3 \sqrt{3}  - 1}{ {(3 \sqrt{3} )  {}^{2}   - (1)}^{2}  }  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \: \:  = \frac{3 \sqrt{3} - 1 }{27 - 1}  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:   =  \frac{3 \sqrt{3 } - 1 }{26}

HOPE THIS HELPED YOU

PLEASE MARK IT BRAINLIEST

Similar questions