Math, asked by MonsieurBrainly, 1 year ago

rationalise the denominator

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Answered by nikky28
3
Heya,

see the attachment for your answer

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MonsieurBrainly: welcome
Answered by Anonymous
1
Hey buddy !!

Here is yr answer
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 = > \frac{4 \sqrt{3} + 5 \sqrt{2} }{4 \sqrt{3} + 3 \sqrt{2} } \\ \\ = > \frac{4 \sqrt{3} + 5 \sqrt{2} }{4 \sqrt{3} + 3 \sqrt{2} } \times \frac{4 \sqrt{3} - 3 \sqrt{2} }{4 \sqrt{3} - 3 \sqrt{2} } \\ \\ = > \frac{( 4\sqrt{ 3} + 5 \sqrt{2})(4 \sqrt{3} -3 \sqrt{2} ) }{(4 \sqrt{3} + 3 \sqrt{2} )(4 \sqrt{3} - 3 \sqrt{2} )} \\ \\ = > \frac{48 - 12 \sqrt{6} + 20 \sqrt{6} - 30 }{48 - 18} \\ \\ = > \frac{18 + 8 \sqrt{6} }{30}

Hope it hlpz...
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