Question

rationalise the denominator​

Answer 1

$\frac{3}{ \sqrt{5 } - \sqrt{6} }$

We rationalise the denominator by multiplying the expression by the conjugate of the denominator

$( \sqrt{5} - \sqrt{6} )$

$\frac{3. \sqrt{5} - \sqrt{6} }{( \sqrt{5} + \sqrt{6})( \sqrt{5} - \sqrt{6}) } \\ \\ \\ = > \frac{3 \sqrt{5} - 3 \sqrt{6} }{( \sqrt{5}) {}^{2} - ( \sqrt{6}) {}^{2} } \\ = > \frac{3 \sqrt{5} - 3 \sqrt{6} }{5 - 6 } \\ = > \frac{3 \sqrt{5} - 3 \sqrt{6} }{ - 1} \\ = > - 3 \sqrt{5 } + 3 \sqrt{6}$

this is the answer.

hope its helpful^_^