rationalise the denominator 3root2 -2root 3
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1/(3root2 -2root3
=(3root2+2root3)/[{3root2-2root3)(3root2+2root3)
=(3root2+2root3)/[{3root2)^2 -(2root3)^2]
=(3root2+2root3)/(18-12)
=(3root2+2root3)6
=(3root2+2root3)/[{3root2-2root3)(3root2+2root3)
=(3root2+2root3)/[{3root2)^2 -(2root3)^2]
=(3root2+2root3)/(18-12)
=(3root2+2root3)6
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this is the ans for your ques
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