Question

rationalise the denominator 4/√3-2

Answer 1

$\frac{4}{ \sqrt{3} - 2} \times \frac{ \sqrt{3} + 2 }{ \sqrt{3} + 2 } \\ \\ = \frac{4( \sqrt{3} + 2) }{3 - 4} \\ \\ = - 4( \sqrt{3} + 2) \\ \\ = - 4 \sqrt{3} - 8$

Answer 2

$\frac{4}{ \sqrt{3} - 2 }$


By Rationalization,


$\frac{4}{ \sqrt{3 } - 2 } \times \frac{ \sqrt{3} + 2}{ \sqrt{3} - 2 }$


On denominator, (a + b) (a - b) = a² -b²


Applying formula, we get,



$\frac{4( \sqrt{ 3} + 2) }{ {( \sqrt{3} )}^{2} - {(2)}^{2} } \\ \\ \\ = > \frac{4( \sqrt{3} + 2) }{3 - 4} \\ \\ \\ \\ => \frac{4 \sqrt{3 } + 8 }{ - 1} \\ \\ \\ => - 4 \sqrt{3} - 8$