Question

Rationalise the denominator 4/3+ root 3​

Answer 1

$\huge\tt\blue{A᭄nswer:┆☈}$

$\huge \longrightarrow \: \frac{6 - 2 \sqrt{3} }{3} \: Ans.$

Step-by-step explanation:

$\frac{4}{3 + \sqrt{3} }$

Rationalising the denominator , we get

$\longrightarrow \: \frac{4}{3 + \sqrt{3} } \times \frac{3 - \sqrt{3} }{3 - \sqrt{3} }$

$\longrightarrow \: \frac{4 \times 3 - \sqrt{3} }{(3 + \sqrt{3} )(3 - \sqrt{3)} }$

$\longrightarrow \: \frac{4(3 - \sqrt{3} }{(3 {)}^{2} - ( \sqrt{3} {)}^{2} }$

$\longrightarrow \: \frac{4(3 - \sqrt{3}) }{6}$

$\longrightarrow \: \frac{ \cancel {4}^{2} (3 - \sqrt{3}) } { \cancel {6}^{3} }$

$\longrightarrow \: \frac{6 - 2 \sqrt{3} }{3} \: Ans.$

Answer 2

$\huge\bf\pink{Answer}$