Math, asked by kaursukhneet033, 7 months ago

rationalise the denominator 4/3- root 5​

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Answered by Anonymous
1

Answer:

your \: answer \: is \: in \: the \: attachment

Step-by-step explanation:

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Answered by XxItzkillergirlXx
23

 \huge{ \heartsuit} { \underline{ \pmb{ \red{{AnSwEr}}}}}

 \underline{ \pmb{given - }}

 \rightarrow\:\frac{4}{(3 -  \sqrt{5}  )}

 \rightarrow \: \frac{4}{3 -  \sqrt{5} }  \times  \frac{3 +  \sqrt{5} }{3 +  \sqrt{5}}

 \rightarrow \:  \frac{4(3 \sqrt{5} )}{ {3}^{2}  -  { \sqrt{5} }^{2} }

 \rightarrow \:  \frac{4(3 \sqrt{5}) }{9 - 5}

 { \rightarrow} { \boxed{\frac{4(3 \sqrt{5} )}{4} }}

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