Question

rationalise the denominator:-4/(√7+√3​

Answer 1

Answer:

-4√7+4√3/4

Step-by-step explanation:

Hi Aviguru

Here's the answer to your question.

(-4/(√7+√3))×(√7-√3)/(√7-√3)

-4(√7-√3)/(√7^2-√3^2)

-4√7+4√3/(7-3)

-4√7+4√3/4

Hope, it helps.

Answer 2

$\huge {\mathcal{\purple{A}\green{N}\pink{S}\blue{W}\purple{E}\green{R}\pink{!}}}$

$\frac{ - 4}{ \sqrt{7} + \sqrt{3} } \\ \\ = \frac{ - 4 \times ( \sqrt{7} - \sqrt{3} )}{( \sqrt{7} + \sqrt{3} )\times( \sqrt{7} - \sqrt{3} ) } \\ \\ = \frac{ - 4 \sqrt{7} + 4 \sqrt{3} }{ {( \sqrt{7} )}^{2} - { (\sqrt{3} )}^{2} } \\ \\ = \frac{4( \sqrt{3} - \sqrt{7} )}{7 - 3} \\ \\ = \frac{4( \sqrt{3} - \sqrt{7} )}{4} \\ \\ = \sqrt{3} - \sqrt{7}$

Hope its helpful ❤️