rationalise the denominator
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(4√5-3√4)/(4√5+3√4)
=(4√5-3√4)(4√5-3√4)/(4√5+3√4)(4√5-3√4)
=(4√5-3√4)²/[(4√5)²-(3√4)²]
=[(4√5)²+(3√4)²-2(4√5)(3√4)]/[(16×5)+(9×4)]
=[(16×5)+(9×4)-(24√20)]/(80+36)
=(80+36-24√20)/116
=(116-24√20)/116(ANSWER)
=(116/116)-(24√20/116)
=1-6√20/29
(ANSWER)
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=(4√5-3√4)(4√5-3√4)/(4√5+3√4)(4√5-3√4)
=(4√5-3√4)²/[(4√5)²-(3√4)²]
=[(4√5)²+(3√4)²-2(4√5)(3√4)]/[(16×5)+(9×4)]
=[(16×5)+(9×4)-(24√20)]/(80+36)
=(80+36-24√20)/116
=(116-24√20)/116(ANSWER)
=(116/116)-(24√20/116)
=1-6√20/29
(ANSWER)
#Mark as the Brainliest
Regards
Team Kancha
dfUtkarsh1:
answer is wrong
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