Rationalise the denominator *
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Answer:
3-√5/3+2√5
by rationalising
3-√5/3+2√5*3-2√5/3-2√5
3-√5(3-2√5)/3+2√5(3-2√5)
3(3-2√5)-√5(3-2√5)/3+2√5(3-2√5)
9-6√5-3√5+10/3+2√5(3-2√5)
19-9√5/3+2√5(3-2√5)
By using identity a²-b²=(a-b)(a+b)
19-9√5/(3)²-(2√5)²
19-9√5/9-10
19-9√5/1
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