Question

Rationalise the denominator​

Answer 1

Answer:

$\frac{3 - 2\sqrt{2} }{3 + 2 \sqrt{2} } \\ \\ = \frac{3 - 2 \sqrt{2} }{3 + 2 \sqrt{2} } \times \frac{3 - 2 \sqrt{2} }{3 - 2 \sqrt{2} } \\ \\ = \frac{9 - 6 \sqrt{2} - 6 \sqrt{2} + 8 }{ {(3)}^{2} - ( {2 \sqrt{2}) }^{2} } \\ \\ = \frac{17 - 12 \sqrt{2} }{9 - 8} \\ \\ = \frac{17 - 12 \sqrt{2} }{1} = 17 - 12 \sqrt{2}$