Question

rationalise the denominator ​

Answer 1

Step-by-step explanation:

√3-√2/√3+√2

multiply denominator and numenator by √3 ,√2

= {√3+√2}*2/{√3-√2} {√3-√2}

= 3+2+2√6/3+2 =5+2√ 6

Answer 2

$\mathtt \color{blue}{\frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} + \sqrt{2} } }$

$\mathtt \color{blue}{\frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \times \frac{ { \sqrt{3} - \sqrt{2} } }{ \sqrt{3} - \sqrt{2} } }$

$\mathtt \color{blue}{\frac{ (\sqrt{3} - \sqrt{2}) {}^{2} }{ (\sqrt{3} )^{2} +( \sqrt{2}) {}^{2} } }$

$\mathtt \color{blue}{ \frac{ { (\sqrt{2} )}^{2} + (\sqrt{3} ) {}^{2} - 2 \times \sqrt{3} \times \sqrt{2} }{3 + 2} }$

$\mathtt \color{blue}{\frac{5 - 2 \sqrt{6} }{5} }$

$\huge\mathtt \color{pink}{HOPE~IT~HELPS}$