Question

Rationalise the denominator
√48+√27/4√3+5√2

Answer 1

Hello Mate here is your answer,

$\sqrt{48} + \frac{ \sqrt{27} }{4 \sqrt{3} } + 5 \sqrt{2} \\ = > \sqrt{4 \times 4 \times 3} + \frac{ \sqrt{3 \times 3 \times 3} }{4 \sqrt{3} } + 5 \sqrt{2} \\ = > 4 \sqrt{3} + \frac{3 \sqrt{3} }{4 \sqrt{3} } + 5 \sqrt{2} \\ = > 4 \sqrt{3} + \frac{3}{4} + 5 \sqrt{2} \\ = > \frac{4 \times 4 \sqrt{3} + 3 + 4 \times 5 \sqrt{2} }{4} \\ = > \frac{16 \sqrt{3} + 3 + 20 \sqrt{2} }{4} \\ = > \frac{3 + 16 \sqrt{3} + 20 \sqrt{3} }{4}$

I hope that helps you