Math, asked by durgesh4992, 9 months ago

rationalise the denominator √6/√2+√3​

Answers

Answered by Anonymous
8

Answer:

√6/√2+√3

= √6/√2+√3 × √2-√3/√2-√3

= √6(√2-√3)/√2^2-√3^2

= √6(√2-√3)/2-3

= √6(√2-√3)/-1

= -√6(√2-√3)

= -√12+√18

= -2√3+3√2 ans

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