rationalise the denominator 6/√3+1
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6/(√3+1) = 6/(√3+1) × (√3-1)/(√3-1)
(6√3-6)/(√3^2-1^2) = (6√3 - 6) / 2 = 3√3 - 3
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Answer:
6 / ✓3+1 (x) ✓3-1 / ✓3-1
6(✓3-1) / (✓3+1)(✓3-1)
6✓3 - 6 / 3-1
6(✓3-1) / 2
6(1.732-1) / 2
6(0.732) / 2
4.4 / 2
2.2
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