Math, asked by puja24377, 2 months ago

rationalise the denominator 6/√3+1​

Answers

Answered by Anonymous
2

6/(√3+1) = 6/(√3+1) × (√3-1)/(√3-1)

(6√3-6)/(√3^2-1^2) = (6√3 - 6) / 2 = 3√3 - 3

Answered by file69
0

Answer:

6 / ✓3+1 (x) ✓3-1 / ✓3-1

6(✓3-1) / (✓3+1)(✓3-1)

6✓3 - 6 / 3-1

6(✓3-1) / 2

6(1.732-1) / 2

6(0.732) / 2

4.4 / 2

2.2

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