Question

rationalise the denominator√6/√3-√2​

Answer 1

Answer:

$3 \sqrt{2} + 2 \sqrt{3}$

Step-by-step explanation:

$\frac{ \sqrt{6} }{ \sqrt{3} - \sqrt{2 } } \\ muliply \: by \: its \: conjugte \\ \frac{ \sqrt{6} }{ \sqrt{3} - \sqrt{2} } \times \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \\ \frac{ \sqrt{6} ( \sqrt{3} + \sqrt{2} ) }{ {( \sqrt{3} })^{2} - {( \sqrt{2} }^{2} )} \\ \frac{3 \sqrt{2} + 2 \sqrt{3} }{3 - 2} \\ \frac{3 \sqrt{2} + 2 \sqrt{3} }{1} \\ 3 \sqrt{2} + 2 \sqrt{3}$