Question

rationalise the denominator 6/3+√5​

Answer 1

Answer:

$\frac{6}{3 + \sqrt{5} } \\ \frac{6}{3 + \sqrt{5} } \times \frac{3 - \sqrt{5} }{3 - \sqrt{5} } \\ \frac{6(3 - \sqrt{5} )}{( {3})^{2} - ({ \sqrt{5} )}^{2} } \\ \frac{6(3 - \sqrt{5}) }{9 - 5} \\ \frac{6 (3 - \sqrt{5} )}{4} \\ \frac{3(3 - \ \sqrt{5}) }{2} \\ \boxed { \frac{9 - 3 \sqrt{5} }{2}}$

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