Question

rationalise the denominator 6/3+√7​

Answer 1

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$\implies \frac{6}{3 + \sqrt{7} } \\ \\ = \frac{6}{3 + \sqrt{7} } \times \frac{3 - \sqrt{7} }{3 - \sqrt{7} } \\ \\ = \frac{6(3 - \sqrt{7)} }{(3 + \sqrt{7)}(3 - \sqrt{7)} } \\ \\ = \frac{18 - 6 \sqrt{7} }{(3) {}^{2} - ( \sqrt{7)} {}^{2} } \\ \\ = \frac{18 - 6 \sqrt{7} }{9 - 7} \\ \\ = \cancel \frac{18 - 6 \sqrt{7} }{2} \\ \\ = \frac{9 - 3 \sqrt{7} }{1} \\ \\ = 9 - 3 \sqrt{7}$

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Answer 2

Answer:

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