Question

rationalise the denominator 6-4root 3 / 6+4root 3

Answer 1

HELLO........FRIEND!!

THE ANSWER IS HERE,

$= > \: \frac{6 - 4 \sqrt{3} }{6 + 4 \sqrt{3} }$

$= > \: \frac{6 - 4 \sqrt{3} }{6 + 4 \sqrt{3} } \times \frac{ 4 \sqrt{3} - 6}{4 \sqrt{3} - 6 }$

$= > \: \frac{ - ( {6 - 4 \sqrt{3}) }^{2} }{ ( {4 \sqrt{3} )}^{2} - {6}^{2} }$

$= > \: \frac{ - 36 - 48 + 48 \sqrt{3} }{12}$

$= > \: \frac{ - 84 + 48 \sqrt{3} }{12}$

$= > \: 4 \sqrt{3} - 7$


:-)Hope it helps u.

Answer 2

Refer the attachment for your answer.

HOPE HELPS