rationalise the denominator √6/√5-√2
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Hi ,
6/( √5 + √2 )
= [ 6( √5 - √2 ) ] / [ (√5 + √2 )(√5-√2)]
= [ 6( √5 - √2 ) ] / [ ( √5 )² - ( √2 )² ]
= [ 6(√5 - √2 ) ]/ ( 5 - 2 )
= [ 6(√5 - √2 ) ] / 3
= 2 ( √5 - √2 )
I hope this helps you.
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