Question

rationalise the denominator √6+√5/√6-√5​

Answer 1

$\huge\mathfrak\red{Answer}$

$\frac{ \sqrt{6 } + \sqrt{5} }{ \sqrt{6} - \sqrt{5} } \\ = \frac{ \sqrt{6 } + \sqrt{5} }{ \sqrt{6} - \sqrt{5} } \times \frac{\sqrt{6} + \sqrt{5} }{ \sqrt{6} + \sqrt{5} } \\ = ({\sqrt{6} + \sqrt{5})}^{2} \\ = 6 + 5 + 2 \sqrt{30} \\ = 11 + 2 \sqrt{30}$