Question

Rationalise the denominator: 6/√7-√3

Answer 1

Answer:

$\frac{6}{ \sqrt{7} - \sqrt{3} } \times \frac{ \sqrt{7} + \sqrt{3} }{ \sqrt{7} + \sqrt{3} } \\ \frac{6 \sqrt{7} + 6 \sqrt{3} }{7 - 3} = \frac{6 \sqrt{7 } + 6 \sqrt{3} }{4}$