Question

Rationalise the denominator
6 by 3+ root 7​

Answer 1

Answer is:-

$\frac{18 - 6 \sqrt{7} }{2}$

Step by step explanation:-

$= \frac{6}{3 + \sqrt{7} } \times \frac{3 - \sqrt{7} }{3 - \sqrt{7} }$

$= \frac{6(3 - \sqrt{7)} }{ {(3)}^{2} - { \sqrt{(7)} }^{2} }$

$= \frac{18 - 6 \sqrt{7} }{9 - 7}$

$= \frac{18 - 6 \sqrt{7} }{2}$

Hope it helps you dear.......xd

Answer 2

$\implies \: \frac{6}{3 + \sqrt{7} } \\ \\ \implies \: \frac{6}{3 + \sqrt{7} } \times \frac{3 - \sqrt{7} }{3 - \sqrt{7} } \\ \\ \implies \: \frac{6(3 - \sqrt{7}) }{ {3}^{2} - ( \sqrt{7} ) ^{2} } \\ \\ \implies \: \frac{18 - 6 \sqrt{7} }{9 - 7} \\ \\ \implies \: \frac{18 - 6 \sqrt{7} }{2}$