Question

rationalise the denominator 6/root8-3​

Answer 1

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Ur answer is in the attachment...

Answer 2

$\dfrac{6}{\sqrt{8} \: - 3}$

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• We have to rationalize its denominator

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$\dfrac{6}{\sqrt{8} \: - 3}$

Rationalize it..

$\Rightarrow\:\dfrac{6}{\sqrt{8} \: - \: 3 } \times \: \dfrac{ \sqrt{8} \: + \: 3 }{ \sqrt{8} \: + \: 3 }$

$\Rightarrow\:\dfrac{6( \sqrt{8} \: + \: 3) }{ {( \sqrt{8} )}^{2} \: - \: {( 3) }^{2} }$

$\Rightarrow\:\dfrac{6 \sqrt{8} \: + \: 18}{ 8 \: - \: 9 }$

$\Rightarrow\:\dfrac{6 \sqrt{8} \: + \: 18}{- \: 1 }$

$\Rightarrow\:18\:-\:6\sqrt{8}$

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$18\:-\:6\sqrt{8}$

________ [ ANSWER ]

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