Question

Rationalise the denominator 6 upon, 2 root 3 ,plus root 6

Answer 1

Answer:

6 / (2√3 + √6)

=6(2√3 - √6) / (2√3 + √6)(2√3 - √6)

=6(2√3 + √6) / [(2√3)^2-(√6)^2]

=6(2√3 + √6) / (12-6)

=(12√3+6√6) / 6

=6(2√3+1√6)/6

=6/6 x (2√3+1√6)/1

=2√3 + √6

Hope this helps :)

Answer 2

Step-by-step explanation:

$\frac{6}{2 \sqrt{3} + \sqrt{6} }$

=

$\frac{6}{2 \sqrt{3} + \sqrt{6} } \times \frac{2 \sqrt{3} - \sqrt{6} }{2 \sqrt{3} - \sqrt{6} }$

=

$\frac{6(2 \sqrt{3} - \sqrt{6}) }{ {2 \sqrt{3} }^{2} - { \sqrt{6} }^{2} }$

=

=

$\frac{6(2 \sqrt{3} - \sqrt{6}) }{12 - 6}$

=

$2 \sqrt{3 } - \sqrt{6}$