Question

Rationalise the denominator 7/√12-√5​

Answer 1

Answer: I hope the answer is helpful for you.

Answer 2

The rationalized value is $\sqrt{12}+\sqrt{5}$.

Given: $\frac{7}{\sqrt{12}-\sqrt{5} }$

To find: rationalizing the denominator

Solution:

$\frac{7}{\sqrt{12}-\sqrt{5} }$

= $\frac{7}{\sqrt{12}-\sqrt{5} } \times\frac{\sqrt{12} + \sqrt{5} }{\sqrt{12} +\sqrt{5} }$

= $\frac{7 (\sqrt{12}+\sqrt{5} ) }{(\sqrt{12}) ^{2} -(\sqrt{5}) ^{2} }$

= $\frac{7 (\sqrt{12} + \sqrt{5} )}{12-5}$

= $\frac{7(\sqrt{12} + \sqrt{5}) }{7}$

7 gets canceled in the numerator and denominator and we get,

= $\sqrt{12}+\sqrt{5}$

Answer: The rationalized value is $\sqrt{12}+\sqrt{5}$.

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