Rationalise the denominator
7√3/√10-√2
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Answer:
7√3/(√10-√2)
=7√3(√10+√2)/(√10+√2)(√10-√2)
=7√3(√10+√2)/(√10)^2-(√2)^2
=7√3(√10+√2)/10-2
7√3(√10+√2)/8
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