Question

Rationalise the denominator 7+3√5/3+√5

Answer 1

Answer:

$\frac{7 + 3 \sqrt{5} }{3 + \sqrt{5} } \times \frac{3 - \sqrt{5} }{3 - \sqrt{5 } } \\ = \frac{(7 + 3 \sqrt{5} ) \times (3 - \sqrt{5)} }{(3 + \sqrt{5})(3 - \sqrt{5}) \ } \\ = \frac{21 - 7 \sqrt{5 } + 9 \sqrt{5} - 15}{9 - 5} \\ = \frac{6 + 2 \sqrt{5} }{4}$

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