Math, asked by Prarthna9541, 11 months ago

Rationalise the denominator—
7+3root5/7-3root5

Answers

Answered by kanishka7830
6

 \frac{7 + 3 \sqrt{5} }{7 - 3 \sqrt{5} }  \\   \frac{(7 + 3 \sqrt{5}) \times (7 + 3 \sqrt{5} ) }{(7 - 3 \sqrt{5})  \times (7 + 3 \sqrt{5} )}  \\ \frac{( {7 + 3 \sqrt{5} )}^{2} }{ {7}^{2} -  {(3 \sqrt{5} )}^{2}  }   \\  \frac{49 + 45 + 42 \sqrt{5} }{49 - 45}  \\  \frac{94 + 42 \sqrt{5} }{4}    \\  \frac{47 + 21 \sqrt{5} }{2}

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