Question

rationalise the denominator 8 upon√3+√5

Answer 1

Hey !!!

8 / √3 + √5

using rationalising process .

8 × (√3 - √5) / √3 + √5 × ( √3 - √5)

8( √3 - √5 ) / (√3)² - (√5)²

8 ( √3 - √5) / 3 - 5

8 ( √3 - √5 ) / -2

- 4 ( √3 - √5 ) = ( - 4√3 + 4√5)

or, ( 4√5 - 4√3 )

or, 4 ( √5 - √3) Answer

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Hope it helps you !!!

@Rajukumar111

Answer 2

Hii !!

$\frac{8}{ \sqrt{3} + \sqrt{5} }$

On rationalizing the denominator we get,

$\frac{8}{ \sqrt{3} + \sqrt{5} } \times \frac{ \sqrt{3} - \sqrt{5} }{ \sqrt{3} - \sqrt{5} } \\ \\ = \frac{8 \sqrt{3} - 8 \sqrt{5} }{ {( \sqrt{3} )}^{2} - {( \sqrt{5}) }^{2} } \\ \\ = \frac{8 \sqrt{3} - 8 \sqrt{5} }{3 - 5} \\ \\ = \frac{8 \sqrt{3} - 8 \sqrt{5} }{ - 2} \\ \\ = \frac{ - 8 \sqrt{3} + 8 \sqrt{5} }{2} \\ \\ = - 4 \sqrt{3} + 4 \sqrt{5} \\ \\ = 4 \sqrt{5} - 4 \sqrt{3} \\ \\ = 4( \sqrt{5} - \sqrt{3} )$

Hope this helps ☺