Math, asked by siddhanth200416, 1 year ago

rationalise the denominator​

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Answered by Sam2292
2

Multiply it by (5√6+2√12)/(5√6+2√12)

Answered by OoINTROVERToO
0

  \tt\frac{4 \sqrt{12} - 7 \sqrt{6}  }{5 \sqrt{6}  - 2 \sqrt{12} }  \\  \\   \tt\frac{4 \sqrt{12} - 7 \sqrt{6}  }{5 \sqrt{6}  - 2 \sqrt{12} } \times   \tt\frac{5\sqrt{6}  +  2 \sqrt{12}  }{5 \sqrt{6}   +  2 \sqrt{12} } \\  \\ \tt\frac{(4 \sqrt{12} - 7 \sqrt{6})(  5\sqrt{6}  +  2 \sqrt{12} )}{(5 \sqrt{6})²  - (2 \sqrt{12})² }  \\  \\  \frac{36 \sqrt{2}-114 }{102}  \\  \\  \frac{6 \sqrt{2}-19 }{17}

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