Rationalise the denominator a)1/2+root3 b)5/root3-root 5 c)1/3root2
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1) 1/2+√3=1/2+√3*2-√3/2-√3
2-√3/ 2^2-√3^2 . (a+B)(a-b)=a^2-b^2
2-√3/4-3
2-√3/1
2-√3
2) √3/√5=√3/√5*√5/√5
then
=√15/√25
=√15/√25*√/√
then
=15/25
=3/5
3) I think it's answer is 1/3√2
2-√3/ 2^2-√3^2 . (a+B)(a-b)=a^2-b^2
2-√3/4-3
2-√3/1
2-√3
2) √3/√5=√3/√5*√5/√5
then
=√15/√25
=√15/√25*√/√
then
=15/25
=3/5
3) I think it's answer is 1/3√2
Answered by
0
Following are the answers :
a. 1 / 2 + √ 3 × 2 - √ 3 / 2 - √ 3
= 1 ( 2 - √ 3 ) / ( 2 + √ 3 ) ( 2 - √ 3 )
= 2 - √ 3 / ( 2 ) ^ 2 - ( √ 3 ) ^ 2
= 2 - √ 3 / 4 - 3
= 2 - √ 3 / 1
= 2 - √ 3.
b. 5 / √ 3 - √ 5 × √ 3 + √ 5 / √ 3 + √ 5
= 5 ( √ 3 + √ 5 ) / [ (√ 3 ) ^ 2 - ( √ 5 ) ^ 2
= 5 ( √ 3 + √ 5 ) / 3 - 5
= 5 ( √ 3 + √ 5 ) / - 2.
c. 1 / 3 √ 2
= 1 ( 3 - √ 2 ) / ( 3 √ 2 ) ^ 2
= 3 √ 2 / 18
= √ 2 / 6.
[ I WOULD HAVE POSTED THE PICTURE BUT MY CAMERA ISN'T WORKING ]…
ANYWAYS..
HOPE IT HELPED.. :))
a. 1 / 2 + √ 3 × 2 - √ 3 / 2 - √ 3
= 1 ( 2 - √ 3 ) / ( 2 + √ 3 ) ( 2 - √ 3 )
= 2 - √ 3 / ( 2 ) ^ 2 - ( √ 3 ) ^ 2
= 2 - √ 3 / 4 - 3
= 2 - √ 3 / 1
= 2 - √ 3.
b. 5 / √ 3 - √ 5 × √ 3 + √ 5 / √ 3 + √ 5
= 5 ( √ 3 + √ 5 ) / [ (√ 3 ) ^ 2 - ( √ 5 ) ^ 2
= 5 ( √ 3 + √ 5 ) / 3 - 5
= 5 ( √ 3 + √ 5 ) / - 2.
c. 1 / 3 √ 2
= 1 ( 3 - √ 2 ) / ( 3 √ 2 ) ^ 2
= 3 √ 2 / 18
= √ 2 / 6.
[ I WOULD HAVE POSTED THE PICTURE BUT MY CAMERA ISN'T WORKING ]…
ANYWAYS..
HOPE IT HELPED.. :))
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