Rationalise the denominator..(a). 6-3√2\6+3√2
Please give step by step expla nation...
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Answer:
The rationalised value is
(6-3√2)/(6+3√2) = (3-2√2)
Step-by-step explanation:
(6-3√2)/(6+3√2)
To rationalize, we multiply (6-3√2) in both numerator and denominator and solving it :-
=(6-3√2)²/(6+3√2)(6-3√2)
={6²+(3√2)²-2.6.3√2 }/6²-(3√2)²
=(36+18-36√2)/36-18
=(54 -36√2)/18
Taking 2 as common from both numerator and denominator and cancelling them:-
=(27-18√2)/9
Again taking 3 as common from both numerator and denominator and cancelling them:-
=(9-6√2)/3
Again taking 3 as common from both numerator and denominator and cancelling them:-
=(3-2√2)/1
The final answer is:-
=(3-2√2)
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