Question

rationalise the denominator and find the value at two decimal places

$\frac{2 + \sqrt{3} }{2 - \sqrt{3} }$
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Answer 1

Answer:

Step-by-step explanation:

Hope thse helps u

Answer 2

Answer:

value=

$7 + 4 \sqrt{3}$

Step-by-step explanation:

$\frac{2 + \sqrt{3} }{2 - \sqrt{3} } \\ = \frac{2 + \sqrt{3} }{2 - \sqrt{3} } \times \frac{2 + \sqrt{3} }{2 + \sqrt{3} } \\ = \frac{4 + 2 \sqrt{3} + 2 \sqrt{3 } + 3 }{4 - 3} \\ = 7 + 4 \sqrt{3}$