Question

rationalise the denominator and simply: i) 3/4-√3​

Answer 1

Answer:

$\frac{3}{4 - \sqrt{3} } \times \frac{4 + \sqrt{3} }{4 + \sqrt{3} }$

$\frac{12 + 3 \sqrt{3} }{(4)^{2} - { (\sqrt{3} )}^{2} }$

$\frac{12 + 3 \sqrt{3} }{16 - 3}$

$\frac{12 + 3 \sqrt{3} }{13}$