Math, asked by Ayaankhan1, 1 year ago

rationalise the denominator.... its urgent

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Answers

Answered by siddhartharao77
7
Given :  \frac{1 +  \sqrt{2} }{2 -  \sqrt{2} }

 \frac{(1+  \sqrt{2} )(2+  \sqrt{2}) }{(2 -  \sqrt{2} )(2 +  \sqrt{2}) }

 \frac{3 \sqrt{2} + 4 }{2^2 - ( \sqrt{2} )^2}

 \frac{3 \sqrt{2}  + 4}{4 - 2}

 \frac{3 \sqrt{2} + 4 }{2}


Hope this helps!

siddhartharao77: Gud luck!
Ayaankhan1: thanks
Answered by sneha798328
1

meet.go

Step-by-step explanation:

Given:

2−

2

1+

2

\frac{(1+ \sqrt{2} )(2+ \sqrt{2}) }{(2 - \sqrt{2} )(2 + \sqrt{2}) }

(2−

2

)(2+

2

)

(1+

2

)(2+

2

)

\frac{3 \sqrt{2} + 4 }{2^2 - ( \sqrt{2} )^2}

2

2

−(

2

)

2

3

2

+4

\frac{3 \sqrt{2} + 4}{4 - 2}

4−2

3

2

+4

\frac{3 \sqrt{2} + 4 }{2}

2

3

2

+4

Hope this help u

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