Question

rationalise. the denominator of 1/(1+√2-√3)

Answer 1

1/(1+root2 - root3)

= 1 × 1-(root2 - root3) / 1+(root2-root3) × 1-(root2-root3)

= 1 - (root2 - root3) / 1^2 - (root2 - root3)^2

= 1 - root2 + root3 / 1 - (2 + 3 - 2root6)

= 1 - root2 + root3 / 1 - 5 + 2root6

= 1 - root2 + root3 / -4 + 2root6


Thanks

Answer 2

the answer is 1-root 2 +root 3/-4-4 root 3