Question

Rationalise the denominator of

1/1+√6-√2​​

Answer 1

Answer:

1 × 1-√6+√2

1+√6-√2 × 1-√6+√2

= 1-√6+√3

(1+√6-√2)(1-√6+√2)

= 1 -√6+√3

1-√6+√2+√6-36+12-√2+12-4

= 1 -√6+√3

1-36+24-4

= 1-√6+√3

-35+20

= 1-√6+√3

-15

Answer 2

Answer:

1/1+√6-√2 •:

Answer = -15