rationalise the denominator of :1-√2/3-2√2
please give me a accurate answer for this
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Step-by-step explanation:
multiplying both numerator and denominator with the denominator of the rational number but with the opposite sign.
I.e 3+3√2
- (1-√2)(3+3√2)/(3-3√2)(3+3√2)
- =(1-√2)(3+3√2)/3^2-(3√2)^2
- =3-2√2+3√2-4/(9-8)
- =√2-1/1
- =√2-1
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