Question

Rationalise the denominator of
1÷2 + √3​

Answer 1

Answer:

Hey! Ur answer:

$\frac{1}{2 + \sqrt{3} } = \frac{1(2 - \sqrt{3)} }{(2 + \sqrt{3)}(2 - \sqrt{3)} } \\ = \frac{2 - \sqrt{3} }{4 - 3} = 2 - \sqrt{3}$

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

$\frac{1}{2 + \sqrt{3} } = \frac{1}{2 + \sqrt{3} } \times \frac{2 - \sqrt{3} }{2 - \sqrt{3} }$

$\frac{2 - \sqrt{3} }{ {2}^{2} - {( \sqrt{3}) }^{2} }$

$\frac{2 - \sqrt{3} }{4 - 3}$

$\frac{2 - \sqrt{3} }{1}$

$2 - \sqrt{3}$