Question

rationalise the denominator of 1/√2+√3+√5

Answer 1

What you have written is actually:

12√+3–√+5–√

[Why? Convention re the order of operations; just like 12/2+1+3 = 6+1+3=10]

The only denominator in this expression is the surd √2

To remove this surd, we just need to multiply the numerator and denominator by √2, thus we have:

12√×2√2√+3–√+5–√

=2√2+3–√+5–√

Somehow, I don’t think this is what you meant!

Instead, I think you meant 1/(√2+√3+√5), which is:

12√+3√+5√

[12/(2+1+3) = 12/6 = 2]

please mark it as brainliest