Math, asked by z9684496, 1 month ago

rationalise the denominator of 1/√2-√5​

Answers

Answered by shreyamallick09
4

Answer:

√5-√2/3 is the answer...

Answered by Unexplained
2

\frac{1}{\sqrt{2} - \sqrt{5} }

Multiplying √2 +√5​ with denominator as well as numerator,

\frac{1 (\sqrt{2} +\sqrt{5}) }{(\sqrt{2} -\sqrt{5} ) ( \sqrt{2} + \sqrt{5} )}

Then, Using formula, ( A + B )  ( A - B )  = A^2 - b^2

= \frac{\sqrt{2} + \sqrt{5} }{( 2 -5 )} \\\\=  \frac{\sqrt{2} + \sqrt{5} }{( -3 )} \\

Hence, Now the denominator is a rational number.

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