Question

rationalise the denominator of 1/√2-√6​

Answer 1

Answer:

$\frac{1}{ \sqrt{2} - \sqrt{6} } \times \frac{ \sqrt{2} + \sqrt{6} }{ \sqrt{2} + \sqrt{6} }$

$\frac{ \sqrt{2} + \sqrt{6} }{ ({ \sqrt{2} )}^{2} - {( \sqrt{6} )}^{2} }$

$\frac{ \sqrt{2} + \sqrt{6} }{2 - 6}$

$\frac{ \sqrt{2} + \sqrt{6} }{ - 4}$

Answer 2

Answer:

2

−

6

1

×

2

+

6

2

+

6

\begin{gathered} \frac{ \sqrt{2} + \sqrt{6} }{ ({ \sqrt{2} )}^{2} - {( \sqrt{6} )}^{2} } \\ \end{gathered}

(

2

)

2

−(

6

)

2

2

+

6

\begin{gathered} \frac{ \sqrt{2} + \sqrt{6} }{2 - 6} \\ \end{gathered}

2−6

2

+

6

\begin{gathered} \frac{ \sqrt{2} + \sqrt{6} }{ - 4} \\ \end{gathered}

−4

2

+

6