rationalise the denominator of 1 / 3 √2 - 2 √ 3 solve
Answers
Answered by
1
Heya !!!!
1/ 3✓2 - 2✓3
=> 1/3✓2 - 2✓3 × ( 3✓2 + 2✓3) / ( 3✓2 + 2✓3)
=> ( 3✓2 + 2✓3 ) / ( 3✓2 - 2✓3 ) ( 3✓2 + 2✓3)
=> ( 3✓2 + 2✓3 ) / (3✓2)² - (2✓3)²
=> ( 3✓2 + 2✓3 ) / 18 - 12
=> ( 3✓2 + 2✓3 ) / 6
★ HOPE IT WILL HELP YOU ★
1/ 3✓2 - 2✓3
=> 1/3✓2 - 2✓3 × ( 3✓2 + 2✓3) / ( 3✓2 + 2✓3)
=> ( 3✓2 + 2✓3 ) / ( 3✓2 - 2✓3 ) ( 3✓2 + 2✓3)
=> ( 3✓2 + 2✓3 ) / (3✓2)² - (2✓3)²
=> ( 3✓2 + 2✓3 ) / 18 - 12
=> ( 3✓2 + 2✓3 ) / 6
★ HOPE IT WILL HELP YOU ★
Answered by
1
Here is your answer
1÷ 3 root 2 - 2 root 3
1 ÷ 3 root 2 - 2 root 3 × 3 root 2 + 2 root 3
3root 2 - 2root 3 / 3root2² - 2root3²
3root 2 - 2root 3 / 6
Hope it helps you ^_^
1÷ 3 root 2 - 2 root 3
1 ÷ 3 root 2 - 2 root 3 × 3 root 2 + 2 root 3
3root 2 - 2root 3 / 3root2² - 2root3²
3root 2 - 2root 3 / 6
Hope it helps you ^_^
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