Math, asked by jasansidhu313, 7 months ago

rationalise the denominator of 1/√3-√2​

Answers

Answered by prachim463
2

Answer:

 \frac{1}{ \sqrt{3}  -  \sqrt{2} }  \times   \frac{ \sqrt{3}   +   \sqrt{2} }{ \sqrt{3}  +  \sqrt{2} }  \\  \frac{ \sqrt{3} +  \sqrt{2} ) }{( \sqrt{ {3}^{2}}  - ( \sqrt{ {2}^{2} )} }  \\  \frac{ \ sqrt{3}  +  \sqrt{2} }{3 - 2}  \\  \ sqrt{3} +  \sqrt{2}

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