Rationalise the denominator of 1/√3-√2
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Answer:
root3 + root2
Step-by-step explanation:
1/root3 - root2 * root3 + root 2/ root 3 + root 2
root3 + root 2/ 3 - 2 [a^2 - b^2 = (a+b)(a-b)]
root 3 + root2
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