Question

rationalise the denominator of 1/√3-√2​

Answer 1

Hope this picture helps uh

Answer 2

ANSWER:-

$\frac{1} {√3-√2}$

= $\frac{1}{√3-√2} × \frac{√3+√2}{√3+√2}$

= $\frac{√3+√2}{(√3)²-(√2)²}$

= $\frac{√3+√2}{3-2}$

= $\frac{√3+√2}{1}$

= $√3+√2$