Rationalise the denominator of 1/√3+√5+√7
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it is related to real nos.
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This type is done one at a time
(√2 +√3 +√5) = (√2 +√3) +√5)
so multiply both numerator and denominator by (√2 +√3) -√5)
to get ((√2 +√3) -√5))/(( (√2 +√3)^2 -√5) ((√2 +√3) +√5))
= ((√2 +√3) -√5))/((√2 +√3)^2 -5)
= ((√2 +√3) -√5))/((2 +3+ 2√6 -5)
= ((√2 +√3) -√5))/(2√6)
now multiply both numerator and denominator by √6
to get √6((√2 +√3) -√5))/12
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