Question

Rationalise the denominator of 1/3-√7

Answer 1

1/3-√7
rationalizing factor of 3-√7 = 3+√7
then ,
1/3-√7 * 3+√7/3+√7
3+√7/(3-√7)(3+√7)
3+√7/(3)^2-(√7)^2
3+√7/9-7
3+√7/2
hence after rationalizing the denominator the value is = 3+√7/2

Answer 2

Step-by-step explanation:

Step-by-step explanation:

\frac{1}{3 + \sqrt{7} }

3+

7

1

Inorder to rationalize the denominator

multiply and divide with

3 - \sqrt{7}3−

7

it becomes,

\frac{3 - \sqrt{7} }{(3 + \sqrt{7)(3 - \sqrt{7)} } }

(3+

7)(3−

7)

3−

7

\frac{3 - \sqrt{7} }{9 - 7}

9−7

3−

7

\frac{3 - \sqrt{7} }{2}

2

3−

7