Rationalise the denominator of 1/3-√7
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Answered by
17
1/3-√7
rationalizing factor of 3-√7 = 3+√7
then ,
1/3-√7 * 3+√7/3+√7
3+√7/(3-√7)(3+√7)
3+√7/(3)^2-(√7)^2
3+√7/9-7
3+√7/2
hence after rationalizing the denominator the value is = 3+√7/2
rationalizing factor of 3-√7 = 3+√7
then ,
1/3-√7 * 3+√7/3+√7
3+√7/(3-√7)(3+√7)
3+√7/(3)^2-(√7)^2
3+√7/9-7
3+√7/2
hence after rationalizing the denominator the value is = 3+√7/2
Answered by
2
Step-by-step explanation:
Step-by-step explanation:
\frac{1}{3 + \sqrt{7} }
3+
7
1
Inorder to rationalize the denominator
multiply and divide with
3 - \sqrt{7}3−
7
it becomes,
\frac{3 - \sqrt{7} }{(3 + \sqrt{7)(3 - \sqrt{7)} } }
(3+
7)(3−
7)
3−
7
\frac{3 - \sqrt{7} }{9 - 7}
9−7
3−
7
\frac{3 - \sqrt{7} }{2}
2
3−
7
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