Math, asked by nhvbyfchhfu, 1 year ago

rationalise the denominator of 1/3-√7​

Answers

Answered by darkfire
2

Answer:

 \frac{1}{3 -  \sqrt{7} }  \\  \\  \frac{1}{3 -  \sqrt{7} }  \times  \frac{3+  \sqrt{7}}{3 +  \sqrt{7} } \\  \\  \frac{3 +  \sqrt{7} }{(3) {}^{2} - ( \sqrt{7}) {}^{2}  }  \\  \\  \frac{3 +  \sqrt{7} }{9 - 7}  \\  \\  \frac{3 +  \sqrt{7} }{2}

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nhvbyfchhfu: thanks
darkfire: Welcome :)
Answered by Anonymous
0

HeRe Is Your Ans ⤵

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 =  >  \frac{1}{3 -  \sqrt{7} }  \\  \\  =  >  \frac{3 +  \sqrt{7} }{ {(3)}^{2} -  { (\sqrt{7} )}^{2}  }  \\  \\  =  >  \frac{3 +  \sqrt{7} }{9 - 7}  \\  \\   =  > \frac{3 +  \sqrt{7} }{2}

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